Answer:
- $2300000- max profit
- 5.77 years into operation - zero profit time
Step-by-step explanation:
<u>Given function:</u>
It is a quadratic function with general form of y = ax^2 + bx + c
It opens down if a < 0 and gets maximum value at vertex which is determined at x = -b/2a
<u>For the given function vertex is:</u>
<u>Maximum value of p is:</u>
- p(3) = -3*3^2 + 18*3 - 4 = -27 + 54 - 4 = 23 ($2300000)
<u>The time when profit is zero:</u>
- -3t^2 + 18t - 4 = 0
- 3t^2 - 18t + 4 = 0
- t = (18 ± √18² - 4*3*4)/2*3 = (18 ± √276)/6 = (18 ± 16.61)/6
- t = (18 - 16.61)/6 = 0.23 this is the time when company has just started to make profit, it is not applicable as is the past time
- t = (18 + 16.61)/6 = 5.77 years into operation, after this time there will be no profit
C. 0.4 times 6 is 2.4. Hope that helps.
Answer:
A.T.Q
358-169
= 189
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
I think it’s $3.75 for 3. Hope this helped :)
Answer:
I think it is $460.00. Plz correspond it.
