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natita [175]
3 years ago
12

Say your car doesn’t run on straight gasoline and you have to mix the oil with gas together in a specific ratio of 2.4 fl oz of

oil for every gallon of gasoline. If you have 1.5 gallons of gas, how much oil should you add?
Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

3.6 fl oz

Step- by-step explanation:

Well if one gallon equal 2.4 fl oz that would mean that half of a gallon would be half of that amount. Half of that amount would be 1.2 fl oz. we have now found how much a full gallon needs and how much half a gallon need. Now we add these 2 numbers. 2.4 fl oz + 1.2 fl oz = 3.6 fl oz.

Please give me Brainliest.

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(a) P(Y'|M)\approx 0.3297

(b) P(Y|M')\approx 0.8323

(c) P(Y'|M')\approx 0.1323

Step-by-step explanation:

Given table is

                Yes      No      Don't Know      Total

Men          162      92             25               279

Women      258    41              11               310

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According the the conditional probability, if A and B are two event then

P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}

P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}

P(Y'|M)=\frac{92}{279}

P(Y'|M)=0.329749103943

P(Y'|M)\approx 0.3297

(b)

P(Y|M')=\frac{P(Y\cap M')}{P(M')}

P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}

P(Y|M')=\frac{258}{310}

P(Y|M')=0.832258064516

P(Y|M')\approx 0.8323

(c)

P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}

P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}

P(Y'|M')=\frac{41}{310}

P(Y'|M')=0.132258064516

P(Y'|M')\approx 0.1323

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