1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetllana [295]
3 years ago
14

I need help with this please

Mathematics
2 answers:
enyata [817]3 years ago
7 0
To find the area of the given diagram use the formula:

A = 1/2(b1 + b2)(h)

b1 and b2 are the bases.

First we need to find the total length of the second base:

7 + 3 = 10

Now apply the formula:

A = 1/2(7 + 10)(6)
A = 1/2(17)(6)
A = 51 in²

Hope this helps :)
frez [133]3 years ago
5 0
A = (6 x 7) + 1/2(6 x 3)
= 42 + 9
= 51
answer
51 in^2
You might be interested in
Find the acute angle between the two given lines<br><br> y=-2x and y=x
Marina CMI [18]

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

3 0
3 years ago
Find the image of each polygon with the given vertices after a dilation centered at the origin with the given scale factor. J(2,
MAVERICK [17]

Applying a dilation centered at the origin with scale factor k has the effect of multiplying both coordinates of a point by k:

(x,y)\mapsto (kx,ky)

So, in your case, the coordinates of the points double:

J'=(4,8),\quad K'=(8,8),\quad P'=(6,4)

4 0
3 years ago
Joan had a difference of opinion with her boss and hence quit her job
Aleks [24]

Answer:

That sucks.

Step-by-step explanation:

7 0
3 years ago
Multiply the equation 2x+2y=8 by 3. Does the equation have the same solution set?
stepan [7]

Multiply the equation:

2x+2y=8 \mapsto 6x+6y=24

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

2x+2y-8=0

Multiplying this by 3 (or whatever number, for all it matters) gives

3(2x+2y-8)=0

Now, a product is zero if and only if at least one of the factor is zero. So, either 3=0 or 2x+2y-8=0

Since the first is clearly impossible, the second one must be true, which is the original equation.

3 0
3 years ago
You are asked to draw a triangle with side lengths of 3 inches, 4 inches, and 1 inch. How many triangles like this can you draw?
marishachu [46]
I think you can draw two of them.

As you walk around the triangle in the clockwise direction,
you can run into the sides in the order of

                 3  ==>  4  ==>  1

or in the order of

                 3  ==>  1  ==>  4 .

Those are mirror images of each other.  So they're not congruent,
and I think they're considered different triangles.

        
6 0
3 years ago
Other questions:
  • What was the original price if after increase by 30% it becomes $520?
    9·1 answer
  • Is the relationship shown by the data linear? If so, model the data with an equation.
    11·1 answer
  • Which of the following statements is true? A. Congruent angles have the same measure. B. Congruent angles are complementary. C.
    7·1 answer
  • Multiply: (5 ft 6 in) × 4
    8·1 answer
  • After the point B(2, 3) is translated along the vector &lt;5, 7&gt; the image will be located at ?
    14·1 answer
  • Find the missing angles. Round to the nearest hundredth.
    5·1 answer
  • 14. AMKL is an isosceles triangle with MK ML.If MK = 7x - 15, KL = 4x - 6, and ML = 10X - 12, find x and the measure of each sid
    8·1 answer
  • A 440m long road is bejng repaired. At the end of the three days, the workers had repaired 3/4 of the road. What length of the r
    15·2 answers
  • I know that the sequence models value of a car that originally cost $26,500 but loses 10% of its each year. What do you know?
    7·1 answer
  • The absolute value of 4 + 7i is equal to the square<br> root of<br> DONE
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!