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Svetllana [295]
3 years ago
14

I need help with this please

Mathematics
2 answers:
enyata [817]3 years ago
7 0
To find the area of the given diagram use the formula:

A = 1/2(b1 + b2)(h)

b1 and b2 are the bases.

First we need to find the total length of the second base:

7 + 3 = 10

Now apply the formula:

A = 1/2(7 + 10)(6)
A = 1/2(17)(6)
A = 51 in²

Hope this helps :)
frez [133]3 years ago
5 0
A = (6 x 7) + 1/2(6 x 3)
= 42 + 9
= 51
answer
51 in^2
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A pair of parallel lines intersected by a transversal and forms same side interior angles that are in a 5:1 ratio. what are the
kifflom [539]

Answer:

1st side: 150

2nd side: 30

3 0
3 years ago
the height in feet above the ground of an arrow after it is shot can be modeled by y=-16r^2+63r+4.Can the arrow pass over a tree
miss Akunina [59]

Answer:

yes

Step-by-step explanation:

y=-16r^2+63r+4

maximum value of y :

y'=0

-32r +63=0

r= 63/32

y = -16(63/32)²+63(63/32)+4

= -4 + 124 + 4 = 124 ft

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the Arrow can pass over the tree

7 0
3 years ago
Someone explain I don’t get it
belka [17]

Answer:

neither do I'm stuck on that one

8 0
3 years ago
Suppose that F(x) = x2 and G(X) = 2/3 x^2. Which statement best compares the graph of G(x) with the graph of F(x)?
masha68 [24]
<h2>Answer:The graph of G(x) is the graph of F(x) compressed vertically.</h2>

Step-by-step explanation:

Given that F(x)=x^{2} and G(x)=\frac{2}{3}x^{2}

F(x) is always positive because x^{2} is always positive.

G(x) is always positive because \frac{2}{3}x^{2} is always positive.

So,both are always positive.

So,there is no flipping over x-axis.

In F(x),the height of a point at x_{0} is x_{0}^{2}

In G(x),the height of a point at x_{0} is \frac{2}{3}x_{0}^{2}

So,height of any point has less height in G(x) than F(x)

So,the graph of G(x) is the graph of F(x) compressed vertically.

3 0
3 years ago
Factor out the GCF of the three terms, then complete the factorization of 6x3 + 6x2 – 1202.
Fittoniya [83]

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