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AleksAgata [21]
3 years ago
8

Given isosceles right triangle CDE with m∠D = 90, sin C = sin D

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:True

Step-by-step explanation:

Given

\angle D=90^{\circ}

For isosceles triangle , CD=DE (x=y)

from figure,

\sin C=\dfrac{y}{H}\\\\\sin D=\dfrac{x}{H}\\\\\text{CD=DE}\\\\\therefore \sin C=\sin D=\dfrac{x}{H}=\dfrac{y}{H}

Thus, the given statement is true

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What is 1/7+2/3 fractions
cricket20 [7]

Answer:

\frac{17}{21}

Step-by-step explanation:

\frac{1}{7} + \frac{2}{3} ( multiply \frac{1}{7}  by 3 and \frac{2}{3} by 7 to get a common denominator)

\frac{3}{21} + \frac{14}{21} = \frac{17}{21}

5 0
3 years ago
Geometry math question no Guessing and Please show work thank you
KatRina [158]

m\angle DCA=m\angle BCA\ \text{therefore:}\\\\4x=6x-58\ \ \ \ |-6x\\\\-2x=-58\ \ \ |:(-2)\\\\x=29\\\\m\angle DCA=(4x)^o\to m\angle DCA=(4\cdot29)^o=116^o

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4 0
3 years ago
Audrey needs to cut 1 meter of yellow ribbon and 28 centimeters of blue ribbon. In total, how many centimeters of ribbon does sh
ahrayia [7]
128 is your answer!!:)
1 meter=100 cm
So 100+28=128! That's your answer!!:)
3 0
3 years ago
Look at the figure. How many different labeled rays are shown?
Liula [17]

Answer:

10 rays

Step-by-step explanation:

Given in the picture is a straight line extending on both sides with points marked on it as A, B, C, D and E

To find out the rays

The rays are

AB, BC, CD, DE

AC, BD, CE

AD, BE

AE

Hence there are in total 10 rays

6 0
4 years ago
Booker and Reginald both collected insects for a science exhibit-collection. The one hundred eighty-seven insects in Reginalds c
blondinia [14]

Answer:

Insects in Bookers collection = 50 insects

Insects in Reginald collection = 137 insects

Step-by-step explanation:

Total insects collected = 187

Reginalds collection are thirty-seven more than twice the number in Bookers collection.

Let

Insects in Bookers collection = x

Insects in Reginald collection = 2x + 37

How many insects are in Bookers collection?

Total insects collected = Bookers collection + Reginald collection

187 = x + (2x + 37)

187 = x + 2x + 37

187 = 3x + 37

187 - 37 = 3x

150 = 3x

Divide both sides by 3

x = 150 / 3

= 50 insects

Insects in Bookers collection = x

= 50 insects

Insects in Reginald collection = 2x + 37

= 2(50) + 37

= 100 + 37

= 137 insects

Total = 50 + 137

= 187 insects

6 0
3 years ago
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