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Elden [556K]
3 years ago
7

What is the equation of the graph below? A graph shows a parabola that opens up and crosses the x axis at negative two and negat

ive four. y = − (x − 3)2 + 1 y = − (x + 3)2 + 1 y = (x − 3)2 − 1 y = (x + 3)2 − 1
Mathematics
2 answers:
Brrunno [24]3 years ago
6 0

Answer:

y = (x+3)^2 - 1

Step-by-step explanation:

Anastaziya [24]3 years ago
4 0

Answer:

y=(x+3)^{2} -1

Step-by-step explanation:

General equation of a parabola that opens up is y=a(x-h)^{2} +k , a>0

So equation becomes y=(x-h)^{2} +k which implies option A and option B can never be true for this parabola.

Also this parabola's vertex lies in 3rd quadrant where coordinates of both x and y will be negative.

So, the equation of parabola will be of the form y=(x+h)^{2} - k

Hence, option 4 that is y=(x+3)^{2} -1 is correct.


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