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Advocard [28]
4 years ago
5

Solve for x: 5/3 x = 20/21 it's fraction. remember to simplify your fraction

Mathematics
2 answers:
marta [7]4 years ago
7 0

Answer:

x = 4/7

Step-by-step explanation:

5/3 x = 20/21

Multiply by 3/5 on each side to isolate x

3/5 *5/3 x = 20/21 * 3/5

x = 20/21 * 3/5

Rewriting the right hand side

x = 20/5 * 3/21

x =4 * 1/7

x = 4/7

mylen [45]4 years ago
4 0
You could write it as:
\frac{5x}{3} = \frac{20}{21 }
Cross multiply
105x = 60
divide 105 on both sides
Answer:
x = \frac{60}{105}
x = \frac{4}{7}
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Find the length of the rectangle.
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Answer:

C

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Help Please 25 points for real answers
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1. B
 
2. D

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4 years ago
La base de una cartulina rectangular mide 8 cm de altura si le recortamos 3 cm a su altura el area de la nueva cartulina seria 1
aev [14]

Answer:

w=8cm\\h=18.75cm

Step-by-step explanation:

Let:

w=Width\\h=Initial\hspace{3}height\\h_m=Modified\hspace{3}height\\\\Where:\\\\h_m=h-3

The area of the cardboard can be calculated using the formula to find the area of a rectangle:

A=w*h

The area of the new cardboard would be:

A=w*h_m\\\\Where:\\\\w=8\\h_m=h-3\\A=126

So:

126=8*(h-3)\\\\126=8h-24

Solving for h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Therefore, the dimensions of the initial cardboard are:

w=8cm\\h=18.75cm

<u><em>Translation:</em></u>

Sea:

w=Ancho\\h=Altura\hspace{3}inicial\\h_m=Altura\hspace{3}modificada\\\\Donde:\\\\h_m=h-3

El área de la cartulina se puede calcular usando la fórmula para encontrar el área de un rectángulo:

A=w*h

El área de la nueva cartulina sería:

A=w*h_m\\\\Donde:\\\\w=8\\h_m=h-3\\A=126

Entonces:

126=8*(h-3)\\\\126=8h-24

Resolviendo para h:

126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm

Por lo tanto, las dimensiones de la cartulina inicial son:

w=8cm\\h=18.75cm

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Answer: 7 cm

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