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NISA [10]
3 years ago
8

Two buses leave towns 576 kilometers apart at the same time and travel toward each other. One bus travels 12

Mathematics
1 answer:
KIM [24]3 years ago
8 0

Answer:

Rate of slower bus; 90 km/h

Rate of faster bus; 102 km/b

Step-by-step explanation:

We know that formula do distance is;

Distance = speed/time

We are told that One bus travels 12h slower than the other.

Let speed of slower bus be x.

Thus;

Speed of faster bus = x + 12

Speed of slower bus = x

After 3 hours, distance by faster bus = 3(x + 12)

Speed of slower bus = 3x

Since the towns are 576 km apart, then;

3(x + 12) + 3x = 576

Divide through by 3 to get;

x + 12 + x = 192

2x + 12 = 192

2x = 192 - 12

2x = 180

x = 180/2

x = 90 km/h

Faster bus speed = 90 + 12 = 102 km/h

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A right rectangular prism is shown.
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So what you are looking for is the hypotenuse of the triangle DCF. 

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The sqaureroot of that is 10.6. So 10.6 is your answer
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3 years ago
Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).
lesya [120]

Answer:

-7x + 4y = +42

Step-by-step explanation:

Going from point (2, -7) to point (6, 0), x increases by 4 and y increases by 7.  Thus, the slope of the line in question is m = 7/4.

Starting from the equation y = mx + b, and subbing (7/4) for m, 6 for x and 0 for y, we get:

0 = (7/4)(6) + b.  Then b = 42/4, or 21/2.  Thus, we now have y = (7/4)x + 21/2.

We must put this into "standard form."  Multiplying all three terms by 4, we get:

4y = 7x + 42.  Rearranging these terms to fit the "standard form" equation Ax + By = C, we get:

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5 0
3 years ago
given that A=43 degrees , B=82 degrees and c=28, solve triangle ABC. Round to the nearest hundredth. A) C= 93 degrees , b= 33.8
n200080 [17]
A=43°
B=82°
c=28

1) A+B+C=180°
Replacing A=43° and B=82° in the equation above:
43°+82°+C=180°
125°+C=180°
Solving for C. Subtracting 125° both sides of the equation:
125°+C-125°=180°-125°
C=55° (option B or C)

2) Law of sines
a/sin A=b/sin B=c/sin C
Replacing A=43°, B=82°, C=55°, and c=28 in the equation above:
a/sin 43°=b/sin 82°=28/sin 55°

2.1) a/sin 43°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 43°:
sin 43°(a/sin 43°)=sin 43°(28/sin 55°)
a=28 sin 43° / sin 55°
Using the calculator: sin 43°=0.681998360, sin 55°=0.819152044
a=28(0.681998360)/0.819152044
a=23.31185549
Rounded to one decimal place
a=23.3

 2.2) b/sin 82°=28/sin 55°
Solving for a. Multiplying both sides of the equation by sin 82°:
sin 82°(b/sin 82°)=sin 82°(28/sin 55°)
b=28 sin 82° / sin 55°
Using the calculator: sin 82°=0.990268069, sin 55°=0.819152044
b=28(0.990268069)/0.819152044
b=33.84903466
Rounded to one decimal place
b=33.8

Answer: Option B) C=55°, b=33.8, a=23.3
8 0
3 years ago
Round the number 296,386,482 to the nearest million
adelina 88 [10]
297,000,000 is your answer.
3 0
3 years ago
Read 2 more answers
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