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Rina8888 [55]
3 years ago
10

What is the answer to 10.81 ÷ 2.3​

Mathematics
2 answers:
mylen [45]3 years ago
8 0
10.81/2.3 would be 4.7
Angelina_Jolie [31]3 years ago
3 0

Answer:

10.81/2.3 = 0

4.7 = 0

L <> R

Step-by-step explanation:

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HELP ME<br> I WILL GIVE YOU BRAINLIEST
erastovalidia [21]

Answer:

3.0 grams of the element are left after 18 minutes

Step-by-step explanation:

Recall that an exponential decay that can be studied with the following formula for the amount of material (A) as a function of time (t):

A(t)=A_{0} (1-r)^t

Where:

A_{0} is the starting amount of the substance (in our case 820 grams)

r is the rate of decay (which in our case given as 26.8% can be written in decimal form as 0.268

and t is the time in minutes (in our case t = 18 minutes)

Then we have:

A(t)=A_{0} (1-r)^t\\A(18)=820*(1-0.268)^18\\A(18)=820*(0.732)^18\\\\A(18)=2.985grams

Which can be rounded to 3.0 grams

5 0
3 years ago
Read 2 more answers
Motor vehicles sold to individuals are classified as either cars or light trucks (including SUVs) and as either domestic or impo
Rudik [331]

Answer:

a) Probability that vehicle is Light Truck is 0.69

b) Probability that vehicle is imported car is 0.08 or 8%.

Step-by-step explanation:

Part a)

Event that vehicle is a car is given by A. Since, the vehicles can only be classified as cars or light trucks, the event that a vehicle will be light truck will be compliment of A.

i.e. Event that vehicle is a Light Truck = A^{c}

It is given that in recent year 69% of vehicles sold were light trucks, 78% were domestic, and 55% were domestic light trucks.

So, from here we can say that, if a vehicle is randomly selected from all the vehicles the probability that it would be a light truck will be:

P(Vehicle will be Light Truck) = P(A^{c}) = 69% = 0.69

Part b)

Event that vehicle is imported is given by B. We need to find the probability the a randomly chosen vehicle is an imported car i.e. we have to find probability of occurrence of events A and B together, which will be denoted as: P(A and B)

Since, P(A^{c}) = 69% = 0.69

P(A) = 1 - P(A^{c}) = 1 - 0.69 = 0.31

It is also given that 78% of vehicles were domestic. This means, the percentage/probability of imported vehicles is:

P(B) = 1 - 0.78 = 0.22

55% of vehicles were domestic light trucks. This can be expressed as:

P(A^{c}\&B^{c}), the compliment of this event will give us P(A or B).

i.e.

P(A or B) = 1 - P(A^{c} \&B^{c}) = 1 - 0.55 = 0.45

According to the addition rule of probabilities:

P(A or B) = P(A) + P(B) - P(A and B)

Substituting the calculated values gives us:

0.45 = 0.31 + 0.22 - P(A and B)

P(A and B) = 0.08

This means, the probability that vehicle is imported car is 0.08 or 8%.

4 0
3 years ago
Solve the equation and show your work please! <br> 3(2y - 0.3) = 19.4 - y
san4es73 [151]

Answer:

y=2.9

Step-by-step explanation:

3(2y - 0.3) = 19.4 - y

6y-0.9=19.4

6y+y-0.9=19.4

6y+y=19.4+0.9

7y=19.4+0.9

7y=20.3

7y/7=20.3/7 (divid each one by seven. that's what /7 means)

y=2.9

5 0
3 years ago
Glen collects a total of 450 stamps from the United States, Great Britain and India. In his collection, 52% of the stamps are U.
skad [1K]
48 indiana stamps and 48%.
5 0
4 years ago
Look at the scatter plot. Which of these equations is the best representation of the trend line?
dusya [7]
B.
y =  \frac{1}{4} x - 2


because of how the slope (Y over X) is 1/4 and the intercept is (0, 2).

The slope is positive because the line moves to the right.

(for me I remember that /it hurts \doesn't. The line is you moving your arm.)
3 0
3 years ago
Read 2 more answers
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