2 years ago

Does anyone know this?

1 answer:

7 0

I’m pretty sure it’s 38, when you divide you don’t get an answer shown, same for subtraction, and multiplication. when you add you get 38 which is a choice; unless there is a formula i’m missing then this should be the answer

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Plz help I will make you brainliest!Thanks

STatiana [176]

Use the formula V=AbH and 48=16h will be the second step and then divide by 16 and then you get the answer

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3 years ago

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What is the surface area of a rectangular prism that is 12cm by 3cm by 5cm?

Cerrena [4.2K]

A = 2lw + 2lh + 2hw
A = 2(12)(3) + 2(12)(5) + 2(5)(3)
A = 72 + 120 + 30
A = 222 cm squared

Hope this helps!! :)

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2 years ago

Kendra rides her bike to school each day. It takes her 10 minutes to ride 30 blocks. What unit rate expresses the speed of Kendr

Mashcka [7]

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2 years ago

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What is 2x+y=3 and x+y=3<br> 1.{-1.5,0}<br> 2.{0,-1.5]<br> 3.{0,3}<br> 4.{3,0}

Yakvenalex [24]

The answer would be 3. {0,3}.

Remember: {x,y}

2(0)+3=3
0+3=3

0+3=3

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago