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Veseljchak [2.6K]
3 years ago
12

Two steps to solve equation with whole number V/4-15=29

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:u

Step-by-step explanation:

V/4-15=29

Multiply each term by 4

V - 60 = 116

V = 116 + 60

V = 176

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Solve questions 15,16,17, and 18. Will give Brainliest!! Please!!! Show minimal work!
SVEN [57.7K]

15. The terminal side of \frac{3\pi}{2} intercepted the unit circle at:

(0,-1).

This implies that:

(\cos \frac{3\pi}{2}, \sin \frac{3\pi}{2}=(0,-1)

This implies that:

\cos \frac{3\pi}{2}=0,\:and\: \sin \frac{3\pi}{2}=-1

16) We have that: \cot \theta =-\frac{6}{7}.

We illustrate this on the right triangle and apply the Pythagoras Theorem as follows:

h^2=6^2+7^2

h^2=36+49

h^2=85

h=\sqrt{85}

Using the mnemonics SOH-CAH-TOAH, we have:

\sin \theta=-\frac{Opp}{Hyp}=-\frac{7}{\sqrt{85} }=-\frac{7\sqrt{85} }{85}

\cos \theta=\frac{Adj}{Hyp}=\frac{6}{\sqrt{85} }=\frac{6\sqrt{85} }{85}

\tan \theta=-\frac{Opp}{Adj}=-\frac{7}{6}}

\csc \theta=-\frac{Hyp}{Opp}=-\frac{\sqrt{85} }{7}

\sec \theta=\frac{Hyp}{Adj}=\frac{\sqrt{85} }{6}

17. We want to verify that: sin^4x-sin^2x=cos^4x-cos^2x

Verifying from the LHS

\sin^4x-sin^2x=(sin^2x)^2-sin^2x

Recall that from the Pythagorean identity:\sin^2x=1-\cos^2x

\sin^4x-sin^2x=(1-cos^2x)^2-(1-\cos^2x)

\sin^4x-sin^2x=1-2cos^2x+\cos^4x-1+\cos^2x

\sin^4x-sin^2x=\cos^4x-\cos^2x

18.  We have:

\tan^2x\sec^2x+2\sec^2x-\tan^2x=2

\tan^2x\sec^2x+2\sec^2x-\tan^2x-2=0

\sec^2x(\tan^2x+2)-1(\tan^2x+2)=0

(\sec^2x-1)(\tan^2x+2)=0

When (\sec^2x-1)=0, we have

x=0,\pi

When \tan^2x+2=0, \tan^2x=-2

We can see this is not defined for all real values of x.

6 0
3 years ago
Y−3=2(x+1) Complete the missing value in the solution to the equation
asambeis [7]

Answer:

can you tell me the complete question..

coz something is lack in your question..

if you are finding the values of x and y then

x=1 and y=7

3 0
3 years ago
Suppose we take repeated random samples of 50 college students from the same population and determine a 95% confidence interval
zzz [600]

Answer:

B. The intervals are centered around the sample mean GPA.

D. 95% of the intervals will contain the population mean in the long run.

Step-by-step explanation:

Confidence interval:

Depends on two things: The sample mean and the margin of error.

Lower end: Sample mean - margin of error

Upper end: Sample mean + margin of error

This means that the intervals are centered around the sample mean.

x% level:

x% of the intervals will contain the population mean in the long run.

So the true statements are:

B. The intervals are centered around the sample mean GPA.

D. 95% of the intervals will contain the population mean in the long run.

3 0
3 years ago
How would you graph y = 1/2x+2
puteri [66]

Answer:

Dark blue all the way to the left

Step-by-step explanation:

Its Dark blue

8 0
3 years ago
Read 2 more answers
Find the 7th term of the geometric sequence show below<br> 7x, -7x^5, 7x^9,…
Karo-lina-s [1.5K]

Answer:

7x^25 :)

Step-by-step explanation:

1: 7x,

2. 7x^5,

3. 7x^9,

4. 7x^13,

5. 7x^17,

6. 7x^21,

7. 7x^25

Have an amazing day!!

Please rate and mark brainliest!!

8 0
3 years ago
Read 2 more answers
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