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3 years ago

The perimeter of a rectangle is 48 m. The area of the rectangle is 128 square meters. Find the dimensions of the rectangle.

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

l = 16, w = 8

Step-by-step explanation:

Let l = length

Let w = width

Area = w * l

128 = w * l

w = 128/l

Perimeter = 2w + 2l

48 = 2w + 2l

48 = 2(128/l) +2l

48 = 256/l +2l

Multiply everything by l

48l = 256 + 2l^2

l^2 + 128 = 24l

l^2 + 128 -24l = 0

(l-16)(l-8)= 0

L = 16

L = 8

If you try them out, and test it, l = 16 would work:

2(16) + 256/16 = 48

32 + 16 =48

16 * 128/16 = 128

16 * 8= 128

128 = 128

Since I'm not sure if you are in advanced math or not, I will do it simple with guess and check

Try w is

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dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

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The value of constant C can be obtained as:

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$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

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$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

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$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

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2 years ago

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kykrilka [37]

Answer:

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Step-by-step explanation:

You have to apply the area of triangle formula :

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Answer:

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