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marta [7]
3 years ago
10

#1 Combine like terms (AlgebraTiles) 3y2+3y2 #2 -3x2-3x2 #3 X2-3x2

Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Not sure if I'm reading this correctly your post


#1 combine like terms

3y^2+3y^2 = 6y^2


#2


-3x^2-3x^2=-6y^2


#3


X^2-3x^2=-2x^2




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Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun
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Answer:

Amount of money Judy has in her account is \$(7500+n).

Amount of money Tommy has in his account is  \$(22506+3n)

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = \$(7500+n)

Hence Amount of money Judy has in her account is \$(7500+n).

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = 3(7500+n)+6 =22500+3n+6=\$(22506+3n)

Hence Amount of money Tommy has in his account is  \$(22506+3n).

8 0
3 years ago
Find the function r that satisfies the given condition. r'(t) = (e^t, sin t, sec^2 t): r(0) = (2, 2, 2) r(t) = ()
lesantik [10]

Answer:

r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2)

Step-by-step explanation:

A primitive of e^t is e^t+c, since r(0) has 2 in its first cooridnate, then

e^0+c = 2

1+c = 2

c = 1

Thus, the first coordinate of r(t) is e^t + 1.

A primitive of sin(t) is -cos(t) + c (remember that the derivate of cos(t) is -sin(t)). SInce r(0) in its second coordinate is 2, then

-cos(0)+c = 2

-1+c = 2

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Therefore, in the second coordinate r(t) is equal to -cos(t)+3.

Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

2 = tan(0)+c = sin(0)/cos(0) + c = 0/1 + c = 0

Thus, c = 2

As a consecuence, the third coordinate of r(t) is tan(t) + 2.

As a result, r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2).

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Answer:

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Step-by-step explanation:

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I am joyous to assist you anytime.

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