Perfect squares. Solve each equation. Check the solutions. g^2+2/3g+1/9=0

The following information is given for Tripp Company, which uses the indirect<br> method

oee [108]

Answer:

Step-by-step explanation:

1.

The cash flow from operating activities is = $28000.

Working Note:

Net Income $20000

Depreciation expense $3000

Increase in accounts receivable ($2000)

Increase in accounts payable $4000

Decrease in inventory $3000

Net Cash Flow from Operating Activities = 20000 + 3000 – 2000 + 4000 + 3000

Net Cash Flow from Operating Activities = $28000

2.

The cash flow from investing activities = $6000.

Working Note:

Proceeds from sale of equipment $6000

Net cash flow from investing activities = $6000

3.

The cash flow from financing activities = - $2000 or ($2000)

Working Note:

Payment of dividends ($2000)

Net Cash flow from financing activities = - $2000 or ($2000)

7 0

3 years ago

Determine if the sequence is arithmetic. If it is, find the common difference. Is the sequence a function ?

BaLLatris [955]

$6)\\r=a_{n+1}-a_n\to r=a_2-a_1=a_3-a_2=a_4-a_3=...\\\\a_1=-7;\ a_2=-10;\ a_3=-11;\ a_4=-13\\\\a_2-a_1=-10-(-7)=-10+7=-3\\a_3-a_2=-11-(-10)=-11+10=-1\\\\a_3-a_2\neq a_2-a_1\\\\\text{It's not an arithmetic sequence}$

$\r=\dfrac{a_{n+1}}{a_n}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...\\\\8.)\\a_1=4;\ a_2=20;\ a_3=100;\ a_4=500\\\\r=\dfrac{20}{4}=\dfrac{100}{20}=\dfrac{500}{100}=5\\\\10.)\\a_1-30;\ a_2=-45;\ a_3=-50;\ a_4=-65\\\\\dfrac{a_2}{a_1}=\dfrac{-45}{-30}=\dfrac{3}{2}\\\\\dfrac{a_3}{a_2}=\dfrac{-50}{-45}=\dfrac{10}{9}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}$
$12.)\\a_1=-7;\ a_2=-14;\ a_3=-21;\ a_4=-28\\\\\dfrac{a_2}{a_1}=\dfrac{-14}{-7}=2\\\\\dfrac{a_3}{a_2}=\dfrac{-21}{-14}=\dfrac{3}{2}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}\\\\\text{It's a function}$

8 0

3 years ago

PLEASE HELP I WILL MARK BRANLIEST

Finger [1]

Answer:

SAS

Step-by-step explanation:

We must prove that triangles ABC and EDC are congruent.

Since BD bisects AE, then AC is congruent with CE.

Since AE bisects BD, then BC is congruent with CD

Angle C is 90° in the triangle EDC and is also 90° in triangle BCA because they are vertical angles.

Being two sides and the included angle congruent, then both triangles are similar by the SAS theorem.

Answer: SAS

4 0

2 years ago

What is the pattern 3.5 to 13

mars1129 [50]

Adding 9.5 every time

4 0

3 years ago

five and three-tenths times a number plus two and seven-tenths is less than three and three-tenths times a number plus one and s

love history [14]

The number according to the given statement is x<-0.55.

Given the statement is five and three-tenths times a number plus two and seven-tenths is less than three and three-tenths times a number plus one and six-tenths.

A mathematical statement is a meaningful component of words that can be true or false. Simply, they are known as a statement.

Let us assume the given number be x.

According to the given statement,

Five and three-tenths of a number means 5.3x.

And two and seven-tenths means 2.7.

So, five and three-tenths times a number plus two and seven-tenths means 5.3x+2.7. ......(1)

It is also given that three and three-tenths times a number means is 3.3x.

And one and six-tenths means 1.6.

So, three and three-tenths times a number plus one and six-tenths means 3.3x+1.6 .......(2)

Now, we will substitute equation (1) less than equation (2) according to the given statement is

5.3x+2.7<3.3x+1.6

Further, we will subtract 2.7 from both sides, we get

5.3x+2.7-2.7<3.3x+1.6-2.7

5.3x<3.3x-1.1

Now, we will subtract 3.3x from both sides, we get

5.3x-3.3x<3.3x-1.1-3.3x

2x<-1.1

Now, we will divide both sides by 2, we get

2x/2<-1.1/2

x<-0.55

Hence, the number for the given statement "five and three-tenths times a number plus two and seven-tenths is less than three and three-tenths times a number plus one and six-tenths" is -0.55.

Learn more about the algebraic statement from here brainly.com/question/2689808

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5 0

1 year ago