3(4x+3) simplified as an expression is: 12x+9
Answer:
is outside the circle of radius of 
centered at 
.
Step-by-step explanation:
Let 
and 
denote the center and the radius of this circle, respectively. Let 
be a point in the plane.
Let 
denote the Euclidean distance between point and point .
In other words, if is at 
while is at 
, then 
.
Point would be inside this circle if 
. (In other words, the distance between 
and the center of this circle is smaller than the radius of this circle.)
Point would be on this circle if 
. (In other words, the distance between and the center of this circle is exactly equal to the radius of this circle.)
Point would be outside this circle if 
. (In other words, the distance between and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between and :
.
On the other hand, notice that the radius of this circle, 
, is smaller than . Therefore, point would be outside this circle.
Answer:
P(X = x, Y = y) = f(x, y)
Step-by-step explanation:
Let X be a discrete random variable, and suppose that the possible values that it can assume are given by x1, x2, x3, . . . , arranged in some order. Suppose also that these values are assumed with probabilities given by
P(X = xk) = f(xk) k = 1, 2, . . . (1)
It is convenient to introduce the probability function, also referred to as probability distribution, given by
P(X = x) = f(x)
If X and Y are two discrete random variables, we define the joint probability function
of X and Y by
P(X = x, Y = y) = f(x, y)
where f(x, y) ≥ 0
Answer:
there are 4 bathroom towels per basket
Step-by-step explanation:
the equation is 16/4=4 hope this helps :)
Answer:
<h3>25%</h3>
Step-by-step explanation:
Total number of student in the school = 152 students
Number of student that have more than one pet = 38
percentage of the students have more than one pet will be expressed as
% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%
% of student with more than 1 pet = 38/152 * 100
% of student with more than 1 pet = 3800/152
% of student with more than 1 pet = 25%
Hence 25% of the students in the school have more than one pet.
