Answer:
Mosses form spores in capsules
The rigth answer is the picture 4.
In the case of a hypotonic extracellular medium, there will be a large inflow of water to dilute the Na, thereby increasing the cell volume and there will be an explosion of the membrane in places so hemolysis, the contents of the red cell ( Hemoglobin) is released into the blood plasma.
On the other hand, in the case where the extracellular medium is hypertonic, therefore archi concentrated, well it will be the water of the red cell that will come out without damaging the membrane, we will rather have a red cell that is completely flat and non-functional without release. erythrocyte (Hb) content.
I believe it is organ level
Answer:
Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.
Step 2. The hydroxyethyl group is oxidized to an acetyl group, and the electrons are picked up by NAD+, forming NADH (the reduced form of NAD+). The high- energy electrons from NADH will be used later by the cell to generate ATP for energy.
Step 3. The enzyme-bound acetyl group is transferred to CoA, producing a molecule of acetyl CoA. This molecule of acetyl CoA is then further converted to be used in the next pathway of metabolism, the citric acid cycle.
