Answer:
in what number is the question ate
The points on the graph of the inverse variation are of the form:
(x, 8/x)
<h3>
Which ordered pairs are on the graph of the function?</h3>
An inverse variation function is written as:
y = k/x.
Here we know that k = 8.
y = 8/x
Then the points (x, y) on the graph of the function are of the form:
(x, 8/x).
So evaluating in different values of x, we can get different points on the graph:
- if x = 1, the point is (1, 8)
- if x = 2, the point is (2, 4)
- if x = 3, the point is (3, 8/3)
- if x = 4, the point is (4, 2)
And so on.
If you want to learn more about inverse variations:
brainly.com/question/6499629
#SPJ1
Given:
The focus of the parabola is at (6,-4).
Directrix at y=-7.
To find:
The equation of the parabola.
Solution:
The general equation of a parabola is:
...(i)
Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.
The focus of the parabola is at (6,-4).

On comparing both sides, we get

...(ii)
Directrix at y=-7. So,
...(iii)
Adding (ii) and (iii), we get



Putting
in (ii), we get



Putting
in (i), we get


Therefore, the equation of the parabola is
.
Let the points be A,B,C
#A
(leg3)
(leg1)
(leg2)
#B
We have to find perimeter



#C
The length of leg3=17.4units