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nata0808 [166]
1 year ago
9

Please answer all or any of the following:-

Mathematics
2 answers:
adoni [48]1 year ago
8 0
B is 1,226 that’s all I know
Nesterboy [21]1 year ago
5 0

Answer:

a) answer is -56,186

b)answer is 1,226

c)answer is -2,953.76

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On a certain map. 2.5 inches represents 15 miles. Bay City and Greenwood are 4 inches apart on the map. What is the actual dista
lubasha [3.4K]
2.5 =15
4=x
4/2.5= 1.6
15 times 1.6 is 24
8 0
3 years ago
HELP MY GRADE DEPENDS ON THIS!!!!
zaharov [31]

Answer:

in what number is the question ate

5 0
3 years ago
An inverse variation function has a k value of 8. Which ordered pair is on the graph of the function?
Vinvika [58]

The points on the graph of the inverse variation are of the form:

(x, 8/x)

<h3>Which ordered pairs are on the graph of the function?</h3>

An inverse variation function is written as:

y = k/x.

Here we know that k = 8.

y = 8/x

Then the points (x, y) on the graph of the function are of the form:

(x, 8/x).

So evaluating in different values of x, we can get different points on the graph:

  • if x = 1, the point is (1, 8)
  • if x = 2, the point is (2, 4)
  • if x = 3, the point is (3, 8/3)
  • if x = 4, the point is (4, 2)

And so on.

If you want to learn more about inverse variations:

brainly.com/question/6499629

#SPJ1

7 0
2 years ago
Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7
shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

y=\dfrac{1}{4p}(x-h)^2+k                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

(h,k+p)=(6,-4)

On comparing both sides, we get

h=6

k+p=-4                            ...(ii)

Directrix at y=-7. So,

k-p=-7                            ...(iii)

Adding (ii) and (iii), we get

2k=-11

k=\dfrac{-11}{2}

k=-5.5

Putting k=-5.5 in (ii), we get

-5.5+p=-4

p=-4+5.5

p=1.5

Putting h=6, k=-5.5,p=1.5 in (i), we get

y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)

y=\dfrac{1}{6}(x-6)^2-5.5

Therefore, the equation of the parabola is y=\dfrac{1}{6}(x-6)^2-5.5.

4 0
2 years ago
URGENT HELP NEED!!! I WILL REWARD LOTS OF POINTS FOR THIS QUESTION!!! ANY IRRALEVENT OR SILLY QUESTION WILL BE INSTANTLY REPORTE
Ipatiy [6.2K]

Let the points be A,B,C

  • A(0,0)
  • B(24,16)
  • C(8,20)

#A

\\ \bull\sf\leadsto AB=\sqrt{(24-0)^2+(16-0)^2}=\sqrt{24^2-16^2}=\sqrt{576-256}=\sqrt{320}=17.4units(leg3)

\\ \bull\sf\leadsto AC=\sqrt{(8-0)^2+(20-0)^2}=\sqrt{8^2+20^2}=\sqrt{64+400}=\sqrt{464}=21.4units(leg1)

\\ \bull\sf\leadsto BC=\sqrt{(24-8)^2+(26-20)^2}=\sqrt{16^2+(-4)^2}=\sqrt{256+16}=\sqrt{272}=16.4units(leg2)

#B

We have to find perimeter

\\ \bull\sf\leadsto Perimeter=AB+AC+BC

\\ \bull\sf\leadsto Periemter=17.4+16.4+21.4

\\ \bull\sf\leadsto Perimeter=55.2units

#C

The length of leg3=17.4units

5 0
3 years ago
Read 2 more answers
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