Answer:
The perimeter of triangle is 19.8 units
Step-by-step explanation:
we know that
The perimeter of triangle ABC is
the formula to calculate the distance between two points is equal to
step 1
Find the distance AB
we have
substitute in the formula
step 2
Find the distance BC
we have
substitute in the formula
step 3
Find the distance AC
we have
substitute in the formula
step 4
Find the perimeter
substitute the values
Answer:
Option 4. x = 0
Step-by-step explanation:
we know that
The rule of the reflection of a point across the y-axis is equal to
(x,y) -----> (-x,y)
The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same
The coordinates of triangle PQR are
P(1, 4), Q(3, 6), and R(5, 2)
Applying the rule of the reflection across the y-axis we have
P(1, 4) -----> P'(-1, 4)
Q(3, 6) ----> Q'(-3, 6)
R(5, 2)----> R'(-5, 2)
The reflection line is the y-axis
Remember that the equation of the y-axis is x=0
therefore
The equation of the reflection line is x=0
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
• 1 + cot²x = csc²x
Consider the left side
x - 
x
Factorise as a difference of squares
= (csc²x - cot²x)(csc²x + cot²x)
= (1 + cot²x - cot²x)(csc²x + cot²x)
= csc²x + cot²x
= csc²x + csc²x - 1
= 2csc²x - 1 = right side ⇒ verified
Answer:
1a) Obtuse
1b) Alternate inner angles
1c) x = 101 degrees
2a) Obtuse
2b) Alternate outer angles
2c) x = 147 degrees
Step-by-step explanation:
I hoped these helped. If possible, may I have brainliest :)
2+2=4
a^2+b^2=c^2
15^2-4^2
=225-16
=209
