Answer:
The first blank is: 26
The second blank is: 17
The third blank is: 31 - n
Step-by-step explanation:
So basically each row should add up to 31. So for every number they give you (doesn't matter which color ball), you need to subtract it from 31.
That's why for the first blank, 31 - 5 is 26
second blank, 31 - 14 is 17
and so on....
so the resulting function would be 31 - n
n being a random number that is given to you
Answer:
Step-by-step explanation:
All the masses here are based on the main mass of the sand. So we will call sand "x". If there is two times as much cement as sand, then cement is 2x; if there is three times as much stone as sand, then stone is 3x. All of these added together equal a mass of 600 kg:
x + 2x + 3x = 600 so
6x = 600 and
x = 100 kg
There are 100 kg of sand. That means that there is 200 kg of cement and 300 kg of stone
Answer:
1216
Step-by-step explanation:
Plug in 8 everywhere you see x.
8[(7*8)+(12*8)]
Solve, using order of operations (PEMDAS).
8(56+96)
8(152)
1216
Answer:
Plug in your variables value.
Step-by-step explanation:
For your case, plug in -6 into the y slot
12(5+2y)= -(6-9y) +4y
12(5+2x-6)= -(6-9x-6)+4y see if that works!
Answer:
<h3>80 feet</h3>
Step-by-step explanation:
Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16
h is the maximum height reached
t is in seconds
The velocity of the projectile at its maximum height is zero;
velocity v = dy/dt
v = -32t + 64
Since v = 0 at maximum height
0 = -32t + 64
32t = 64
t = 2secs
Substitute t = 2secs into the equation of the height to get the maximum height.
y = −16t^2 + 64t +16
at t = 2secs
y = −16(2)^2 + 64(2) +16
y = -64 + 128 + 16
y = 64+16
y = 80 feet
Hence the maximum height, in feet, reached by the projectile is 80 feet
