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3 years ago

5

in a given year, residents of a country spent approximately $54.7 billion on their pets. Of this amount, $17.6 billion wa for ve

terinarian bills. What percent of the total was spent on veterinary care?

1 answer:

Evgesh-ka [11]3 years ago

3 0

Answer:

32.176 %

Step-by-step explanation:

(100% / 54.7) x 17.6 = about 32.176 percent

Do the equation yourself for a more precise answer!

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Two friends, Parker and David, took summer jobs. The graph below represents David's earnings in dollars and cents, yy, for worki

siniylev [52]

Answer:

WORK For Exercises 44 and 45, use the information below and in the graph. Andrea works in a restaurant and is paid every two weeks. If Andrea earns $ 6.50 an hour, illustrate the Distributive Property by writing two expressions representing Andrea's pay last week.

8 0

2 years ago

The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t

velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 29.9, \sigma = 2.31$

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{34 - 29.9}{2.31}$

$Z = 1.77$

$Z = 1.77$ has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

8 0

3 years ago

Work Out The Value of X

melomori [17]

Answer:

71°

Step-by-step explanation:

3x° + (x - 11)° + (2x - 55)° = 360°

3x + x - 11 + 2x - 55 = 360°

6x - 66 = 360°

6x = 360° + 66°

6x = 426°

x = 71°

8 0

3 years ago

The question is in the picture

AURORKA [14]

Answer:

B: 0.15

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha

VladimirAG [237]

Answer:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

n=369

Step-by-step explanation:

1) Notation and definitions

$X=40$ number of the selected labourers opt for a new incentive scheme.

$n=100$ random sample taken

$\hat p=\frac{40}{100}=0.4$ estimated proportion of the selected labourers opt for a new incentive scheme.

$p$ true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

And rounded up we have that n=369

8 0

3 years ago