The Forms of Account Ownership that i would recommend is the use of:
- An individual account - when it is a sole business.
- A joint tenancy with right of survivorship account - Spouse or married couples, siblings .
- A tenancy by the entirety account - Married couples.
<h3>What is a joint account with right of survivorship?</h3>
Joint tenants that has the right of survivorship (JTWROS) is known to be a form of ownership where the full account passes to the other tenant when there is the death of one of the tenants.
The tenancy that is best for married couples is the one that is mostly used for a married couple and this is known to be Tenants by the Entirety.
Therefore, The Forms of Account Ownership that i would recommend is the use of:
- An individual account - when it is a sole business.
- A joint tenancy with right of survivorship account - Spouse or married couples, siblings .
- A tenancy by the entirety account - Married couples.
Learn more about Account Ownership from
brainly.com/question/25734244
#SPJ1
6 ft 3 inches
1 inch = 0.0833 ft.
A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
-3=(-3/4)(-3) + b
and isolate b:
b-3=(-3/4)(-3)
b=(-3/4)(-3) +3
b=9/4+3
b=21/4
The final equation is y= -4/3x + 21/4
The y intercept is (21/4).
I know that the square root of 49 = 7 since 7 x 7 = 49. But the negative square root of 49 is -7.
<u>Given</u><u> info</u><u>:</u><u>-</u>
Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Find the perimeter of the field ?
<u>Explanation</u><u>:</u><u>-</u>
Given that
rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.
Let consider a rhombus ABCD
Let AC = (d1) = 42 cm
Let BD = (d2) = 56 cm
We know that
The digonals of a rhombus bisects each other at 90°.
AC = AO+OC
⇛ AC = 2 AO = 2 OC
⇛ AO = OC = AC/2
⇛ AO = OC = 42/2 = 21 cm
and
BD = BO+OD
⇛ BD = 2 BO = 2 OD
⇛ BO = OD = BD/2
⇛ BO = OD = 56/2 = 28 cm
We have,
∆AOB is a right angled triangle
By Pythagoras theorem,
AB² = AO²+OB²
⇛ AB² = 21²+28²
⇛ AB² = 441+784
⇛ AB² = 1225
⇛ AB = ±√1225
⇛ AB = ±35
AB is the length of the side which cannot be negative.
AB = 35 cm
We know that
All sides are equal in a rhombus
⇛ AB = BC = CD = DA
As we know
The Perimeter of a rhombus = 4×Side units
The perimeter of the rhombus ABCD
⇛ 4AB = 4BC = 4CD = 4DA
⇛ 4×35 cm
⇛ Perimeter = 140 cm
<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>