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antoniya [11.8K]
3 years ago
8

Write the linear equation in slope-intercept form passing through the point (0, 3) and that has a slope of 2.

Mathematics
1 answer:
Yuri [45]3 years ago
5 0

Answer:

y=2x+3

Step-by-step explanation:

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The Forms of Account Ownership that i  would recommend is the use of:  

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<h3>What is a joint account with right of survivorship?</h3>

Joint tenants that has the right of survivorship (JTWROS) is known to be a form of ownership where the full account passes to the other tenant when there is the death of one of the tenants.

The tenancy that  is best for married couples is  the one that is mostly  used for a married couple and this is known to be Tenants by the Entirety.

Therefore, The Forms of Account Ownership that i  would recommend is the use of:  

  • An individual account - when it is a sole business.
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8 0
2 years ago
The big desk in your boss's office is 75 inches long. How long is that in feet?
Korvikt [17]
6 ft 3 inches
1 inch = 0.0833 ft.
3 0
3 years ago
What is the y-intercept of the line perpendicular to the line y = 3/4x + 3 that includes the point (-3, -3)
kipiarov [429]
A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
-3=(-3/4)(-3) + b
and isolate b:
b-3=(-3/4)(-3)
b=(-3/4)(-3) +3
b=9/4+3
b=21/4

The final equation is y= -4/3x + 21/4
The y intercept is (21/4).
6 0
3 years ago
Bob buys 20 watermelons... <br> He eats 10. If x=x, what is the square root of 49?
vichka [17]
I know that the square root of 49 = 7 since 7 x 7 = 49. But the negative square root of 49 is -7.
8 0
4 years ago
Read 2 more answers
Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
Vlad1618 [11]

<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Find the perimeter of the field ?

<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

6 0
3 years ago
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