In an if...else statement, if the code in the parenthesis of the if statement is true, the code inside its brackets is executed. But if the statement inside the parenthesis is false, all the code within the else statement's brackets is executed instead.
Of course, the example above isn't very useful in this case because true always evaluates to true. Here's another that's a bit more practical:
#include <stdio.h>
int main(void) {
int n = 2;
if(n == 3) { // comparing n with 3 printf("Statement is True!\n");
}
else { // if the first condition is not true, come to this block of code
printf("Statement is False!\n"); } return 0;
}
Output:
Statement is False!
Well, dont know ;-: PROBLEM?
Answer:
Option(c) is the correct answer for the given question.
Explanation:
The method variable overrides the class variable name with same name The method variable overrides of the class variable name .
Following are the example in java language
public class Main
{
int b=90; // class varaible or instance varaible
void sum()
{
int b=34; // method having same name as class varaible name
b=b+10;
System.out.println(b); // display b
}
public static void main(String[] args) // main method
{
Main ob=new Main(); // craete object
ob.sum(); // calling method sum
}
}
Output:
44
In this we declared a variable 'b' as int type in class and override this variable in sum() function it means same variable name is declared in function sum() .
acquiesces ,destroys,alters are the wrong for the given question.
So overrides is the correct answer
