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Whitepunk [10]
4 years ago
5

Number five please help!

Mathematics
1 answer:
jeka57 [31]4 years ago
4 0

Answer:

y+4 = 2(x+3)

Step-by-step explanation:

We have 2 points so we can find the slope

m = (y2-y1)/ (x2-x1)

   = (2--4)/(0--3)

    = (2+4)/(0+3)

    = 6/3

   = 2

We want to use the point slope form of the equation for a line

y-y1 = m(x-x1)

We know the slope =2 and the point (0,2)

y-2 = 2(x-0)

y-2 = 2x

We could also use the other point (-3,-4)

y--4 = 2(x--3)

y+4 = 2(x+3)

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4 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

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7 0
2 years ago
Ellie borrows money at a year simple rate of 6 1/2% after 4 years ellie owes 39 interest
kupik [55]

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I = PRT

39 = P x 0.065 x 4

39 = P x 0.26

Divide both sides by 0.26

150 = P

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2 years ago
{3.1, 4.2, 7.2, 8.4, 12.2}
Romashka-Z-Leto [24]
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