Ask question

Ask question

All categories

ludmilkaskok [199]

3 years ago

12

The endpoints of VW are V(-4,9) and W(1,-6). Find the coordinates of the midpoint M

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

(-3/2 or 1.5, 3/2 or 1.5)

x = -3/2 or -1.5

y = 3/2 or 1.5

Step-by-step explanation:

the midpoint formula is x1+x2/2 and then y1+y2/2 so -4 +1 = -3/2 for x. for y, 9 + -6 = 3/2. so the midpoint would be (-3/2 or 1.5, 3/2 or 1.5) depending on if you’re using decimals or fractions

You might be interested in

Someone help plz

Lilit [14]

Hope this helps !!!!

7 0

3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago

Jina wanted to study how the area of a rectangle changes with the length if it’s width is fixed. She computed the areas of sever

olganol [36]

Answer:

The domain and the range of the function are, respectively:

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

8 0

3 years ago

Ax-4y=-1. (6,1) find coefficient write complete equation

Rom4ik [11]

I think the answer is a=2

7 0

3 years ago

Solve : 2/3+(x)=3 <br> A)-4/3<br> B)-7/3<br> C)4/3<br> D)7/3

snow_tiger [21]

Answer:

a

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers