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BARSIC [14]
2 years ago
12

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Mathematics
1 answer:
gogolik [260]2 years ago
3 0

Answer:

a = 4

b = 4

Step-by-step explanation:

This is a special right triangle with angle measures of 45° 45° 90° and side lengths x x x√2

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What fraction is equal to the length of the red segment? Please answer in fraction form and how to get the answer
strojnjashka [21]
Answer:
The red segment is from 1/4 to 3/4.
3/4 - 1/4 = 2/4
2/4 = 1/2
1/2

This answer can also be found by seeing there are four equal boxes making up the one larger box, since two out of the four boxes are filled then the fraction would be 2/4, which simplifies to 1/2
6 0
2 years ago
What can I add to get -6?
krok68 [10]
So what you would need to add to get -6 is -5-1 then your answer would be -6 hope this helps!
3 0
1 year ago
Read 2 more answers
I’m confused on this one
Mandarinka [93]

Remark

If the lines are parallel then triangle RQS will be similar to triangle RTP


From that, all three lines in one triangle will bear the same ratio to all three lines of the second triangle.


Givens

PQ = 8

QR = 5

RS = 15

ST = x + 3


Ratio

QR/RP = RS/RT


Sub and solve

RP = 5 + 8

RP = 13


RT = 15 + x + 3

RT = 18 + x


5/13 = 15 / (18 + x) Cross multiply

5(18 + x) = 195 Remove the brackets on the left.

90 + 5x = 195 Subtract 90 from both sides.

5x = 105 Divide by 5

x = 105/5

x = 21 Answer <<<<<<<

3 0
2 years ago
What does it mean to have diagonals bisect each other?
Degger [83]

Answer:

I think your answer would be A

Step-by-step explanation:

8 0
2 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
2 years ago
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