Answer:
0.14
Step-by-step explanation:
From the question given above, the following data were obtained:
Grade A = 5
Grade B = 10
Grade C = 15
Grade D = 3
Grade F = 2
Sample space (S) = 35
Probability of getting grade A, P(A) =?
The probability that a student obtained a grade of A can be obtained as follow:
Probability of getting grade A, P(A) =
Event of A (nA) / Sample space, (nS)
P(A) = nA/nS
P(A) = 5/35
P(A) = 0.14
Thus, probability that a student obtained a grade of A is 0.14
Answer:
pi
Step-by-step explanation:
Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)
5/9 + 1/3 = 5/9 + 3/9 = 8/9 <==
