For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
#SPJ1
D: 1/6 * 2 = 2/12
hope this helps :) (please mark brainliest!)
Answer:
9
Step-by-step explanation:
The factors of 18 are : 1, 2, 3, 6, 9, 18
The factors of 27 are : 1, 3, 9, 27
The common factors are : 1, 3, 9
The gcf is 9
I need -487 time to regroup.
i did 426 - 913 = -487
The answer is
<span>B.
The size of the fish Joe can catch is a function of the strength of his fishing line.
</span>
