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disa [49]
3 years ago
14

Need help with this math question please

Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

See below for answer.

Step-by-step explanation:

RP/RT =RQ/RS                  Given

∠R = ∠R

ΔPQR similar to Δ TSR      If the measures of two sides of a triangle are proportional to the measures of two corresponding sides of another triangle and their included angles are congruent, then the triangles are similar.

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Which one i greater 2/8 or 1/2 ?
ryzh [129]
\frac{2}{8}=\frac{1}{4}\\
\frac{1}{2}=\frac{2}{4}\\\\
\frac{2}{4}>\frac{1}{4} \Rightarrow\frac{1}{2}>\frac{2}{8}
5 0
3 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
Dan brought 36 vanilla cupcakes and 49 chocolate cupcakes to his school bake sale. Then his friend brought 5 more cupcakes. How
fomenos

Answer:

90

Step-by-step explanation:

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Step-by-step explanation:

6 0
2 years ago
Would you pls answer this question?
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Answer:

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so h= 3×4= 12feet

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