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3 years ago

Need help with this math question please

Mathematics

1 answer:

lesya692 [45]3 years ago

3 0

Answer:

See below for answer.

Step-by-step explanation:

RP/RT =RQ/RS Given

∠R = ∠R

ΔPQR similar to Δ TSR If the measures of two sides of a triangle are proportional to the measures of two corresponding sides of another triangle and their included angles are congruent, then the triangles are similar.

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Please help asap?......

andriy [413]

Answer:

Step-by-step explanation:

6 0

3 years ago

Which of the following is equivalent to 92 1/2 pounds in ounces

viva [34]

Well first, you have to see how many ounces are in 1 pound and there are 16 ounces in 1 pound.
So now, I am going to multiply 16×92 1/2 ( or 92.5 )
SO: 92.5
× 16
--------------
1480 ounces

7 0

3 years ago

Please answer something relevant to this question ,I really need help with this

belka [17]

First you need to substitute the xs and ys into point slope ( y1 - y2 = m(x1 - x2). in this example it would be 3-6= m(0 - (-1)). then you just simplify, so -3 = m(1) -3=m. the slop is -3. because you already know the y-intercept is 3 (0,3), you can substitute everything into slope intercept (y=mx+b). so the answer is y=-3x+3.

I hope this helped, let me know if you are still confused and i can help :)

5 0

3 years ago

PTC is a substance that has a strong bitter taste for some people and is tasteless for others. The ability to taste PTC is inher

lana66690 [7]

Answer:

a) $n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

b) For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

Step-by-step explanation:

We need to remember that the confidence interval for the true proportion is given by :

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Part a

The estimated proportion for this case is $\hat p =0.76$

Our interval is at 90% of confidence, and the significance level is given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . The critical values for this case are:

$z_{\alpha/2}=-1.64, t_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The margin of error desired is given $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Replacing we got:

$n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

Part b

For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

3 0

3 years ago

Manny is an online student who currently owns an older car that is fully paid for. He drives, on average, 110 miles per week to

Step2247 [10]

Answer:

The new car costs more

Old car = $5062.125

New car = $7161.357

Step-by-step explanation:

Manny drives an average of 110 miles per week with his old car. The old car gets 16 miles per gallon. The cost per gallon is $2.65 repair and Maintainance costs an average of $740 per year.

For the old car, to find the amount spent on the car we have

110/16 * 2.65 = $18.21875 / week

There are 52 weeks in a year. We have

10.21875*52 = $ 947.375

947.375 + 740

= $1687.375

= 1687.357 * 3

= $5062.125

The new car cost $6500 over a three year loan process.

The car gets 28 miles per gallon. It requires a maintenance f $10 per month. For the new car to find the amount, we have

110*28 * 2.65 *52 = $541.357

541.357 + 10(12) + 6500

= $7161.357

5 0

3 years ago