Hello!
First of all, let's add 50 to both sides.
x/-3=50
Now we multiply both sides by -3.
x= -150
I hope this helps!
Answer: 2.87 hours
Step-by-step explanation:
There may be a typo in the question because 55 hours in a day is not logical so you must have meant 5.5 hours.
In that case, the hours he will require on the third day would require the distance left to calculate. Get this distance from the first 2 days.
Day 1 distance travelled = Time * Speed
= 5.5 * 66
= 363 miles
Day 2 distance travelled = Time * Speed
= 5.5 * 58
= 319 miles
Total distance remaining
:= 840 - 363 - 319
= 158 miles
Travelling at 55 miles per hour, the time to be taken is:
= Distance remaining / Speed
= 158 / 55
= 2.87 miles per hour
Step-by-step explanation:
Let vertical height of ladder from ground be y and
horizontal distance of the base of the ladder from the wall be x respectively.
Length of the ladder = l (constant) = 10 ft
<u>Using Pythagoras theorem</u>:
![{l}^{2} = {y}^{2} + {x}^{2}](https://tex.z-dn.net/?f=%20%7Bl%7D%5E%7B2%7D%20%20%3D%20%20%7By%7D%5E%7B2%7D%20%20%2B%20%20%7Bx%7D%5E%7B2%7D%20)
Differentiate both sides w.r.t time
![0 = 2y \frac{dy}{dt} + 2x \frac{dx}{dt}](https://tex.z-dn.net/?f=0%20%3D%202y%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%20%2B%202x%20%5Cfrac%7Bdx%7D%7Bdt%7D%20)
![y \frac{dy}{dt} + x \frac{dx}{dt} = 0](https://tex.z-dn.net/?f=y%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%20%2B%20x%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%3D%200)
<u>We know that</u> (After 1 sec, y = 6 ft and x = 8 ft ; dy/dt = 2 ft/sec)
![6\times 2 + 8\frac{dx}{dt} = 0](https://tex.z-dn.net/?f=6%5Ctimes%202%20%2B%208%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%3D%200)
![\frac{dx}{dt} = - 1.5 ft \: per \: sec](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%3D%20%20-%201.5%20ft%20%20%5C%3A%20per%20%5C%3A%20sec)
<u>( Ignore - ive sign)</u>
Therefore, bottom of the ladder is sliding away from the wall at a speed of 1.5 ft/sec one second after the ladder starts sliding.
Answer:
i believe the answer is true
Step-by-step explanation:
In order of missing boxes, 15 and 76