There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
The answer is A because 5 x 3/8 and 15 x 1/8 both equal 15/8.
Answer:
C. x = 3
Step-by-step explanation:
Step 1:
- 6x + 19 = x - 2
Step 2:
- 7x + 19 = - 2
Step 3:
- 7x = - 21
Step 4:
21 = 7x
Answer:
3 = x
Hope This Helps :)
Answer:
d = 11.401754
For:
(X1, Y1) = (5, 4)
(X2, Y2) = (-4, -3)
Distance Equation Solution:
=√ (-4−5)2+(−3−4)2
=√ (-9)2+(−7)2
=√ 81+49
=√ 130
=11.401754
It would be 3/19. Cause you add all and that would be denom.
