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4 years ago

Which of the following is aqual to 7 1/3

1 answer:

7 0

7 1/3 is written in mixed fraction form.
which is equivalent to 7+ 1/3
now we can simplify this to get another equivalent form of given number
$7+\frac{1}{3}$
$=7*\frac{3}{3}+\frac{1}{3}$
$=\frac{21}{3}+\frac{1}{3}$
$=\frac{21+1}{3}$
$=\frac{22}{3}$
Hence $\frac{22}{3}$ is the required answer.

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3 years ago

Read 2 more answers

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2 years ago

I need help please ASAP im gonna fail if i dont get right will give 51 points

evablogger [386]

1. x = 20 , x² = 400 and x³ = 8000

2. x = 7 , x² = 49 and x³ = 343

Step-by-step explanation:

Given values are;

2000, 7, 400, 20, 4000, 200

We have to find x, x² and x³.

Part 1:

$x^3=8000$

We will take cube root to find x.

$\sqrt[3]{x^3} =\sqrt[3]{8000}$

$x=20$

Now, we will take square;

$(x)^2=(20)^2\\x^2=400$

Therefore;

x = 20 , x² = 400 and x³ = 8000

Part 2:

x² = 49 , x³ = 343

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Therefore;

x = 7 , x² = 49 and x³ = 343

Keywords: cube root, square root

Learn more about cube root at:

#LearnwithBrainly

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4 years ago

Determine whether each function is continuous at x=5. Justify your answer using the continuity test.

irakobra [83]

Answer:

2. $f(x)=\frac{x^2}{x+5}$

Step-by-step explanation:

When you replace x=5 into those functions you obtain:

$1. f(x)=\sqrt{x^2-36} = \sqrt{5^2-36} = \sqrt{-11} \\2. f(x)=\frac{x^2}{x+5}=\frac{5^2}{5+5}=\frac{25}{10}$

We can see that the function number 1, when the x=5 is replaced, falls into the imaginary numbers or complex domain, so the function is not continuous in the real domain.

On the other hand, the second function falls into the real domain whe x=5 is replaced, so the function is continuous in the real domain!

I hope you understand!

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4 years ago