The answer is C: Divide the arc's degree measure by 360°, then multiply by the circumference of the circle.
Explanation.
Let r = radius of the circle
Then the circumference is C = 2πr.
Let the degree measure of the arc be x degrees.
In radians, the angle is (x/180)π radians
The measure of the arc is
r*(x/180)π = (x/180)*πr
= (2x/360)*πr
= (x360)*2πr
= (x/360)*C
This proves the statement for the answer because
x/360 is the degree measure divided by 360,
C is the circumference.
The angle ∠EJS is bisected by the diagonal JS to form an angle of 62°
Response:
<h3>What properties of a rhombus can be used to find ∠EJS = 62?</h3>
Properties of a rhombus:
The lengths of the sides of a rhombus are equal
The measure of the opposite angles of a rhombus are equal
The diagonals bisect the interior angles of a rhombus
Given that JOSE is a rhombus, and ∠ESO = 124°, we have;
∠EJO = ∠ESO = 124° opposite angles of a rhombus
∠EJS = ∠OJS definition of bisected angle ∠EJO
∠EJS + ∠OJS = ∠EJO by angle addition
- ∠EJS + ∠OJS = 2×∠EJS = ∠EJO = 124°

Learn more about a rhombus here:
brainly.com/question/10689502
Answer:
2/3
all you have to do is make 1 1/4 an improper fraction and then use the keep change flip method.
Answer: 
<u>Explanation:</u>
y varies directly with x means:
; where k is the rate
Answer:
Step-by-step explanation:
4
unit digit=4
cube=64