Question

Secant AD and AE intersect in the exterior of a circle. ∠ BAC measures 27.42° and the measure of DE is 73.18°. Determine the measure of BC .

Answer 1

Answer:

BC = 18.34°

Step-by-step explanation:

The secant- secant angle BAC is half the difference of the intercepted arcs, that is

$\frac{1}{2}$ ( DE - BC) = 27.42

$\frac{1}{2}$ ( 73.18 - BC ) = 27.42 ( multiply both sides by 2 )

73.18 - BC = 54.84 ( subtract 73.18 from both sides )

- BC = - 18.34° ( multiply both sides by - 1 )

BC = 18.34°