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svp [43]
3 years ago
12

Secant AD and AE intersect in the exterior of a circle. ∠ BAC measures 27.42° and the measure of DE is 73.18°. Determine the mea

sure of BC .

Mathematics
1 answer:
sveta [45]3 years ago
5 0

Answer:

BC = 18.34°

Step-by-step explanation:

The secant- secant angle BAC is half the difference of the intercepted arcs, that is

\frac{1}{2} ( DE - BC) = 27.42

\frac{1}{2} ( 73.18 - BC ) = 27.42 ( multiply both sides by 2 )

73.18 - BC = 54.84 ( subtract 73.18 from both sides )

- BC = - 18.34° ( multiply both sides by - 1 )

BC = 18.34°

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