Secant AD and AE intersect in the exterior of a circle. ∠ BAC measures 27.42° and the measure of DE is 73.18°. Determine the mea
1 answer:
Answer:
BC = 18.34°
Step-by-step explanation:
The secant- secant angle BAC is half the difference of the intercepted arcs, that is
( DE - BC) = 27.42
( 73.18 - BC ) = 27.42 ( multiply both sides by 2 )
73.18 - BC = 54.84 ( subtract 73.18 from both sides )
- BC = - 18.34° ( multiply both sides by - 1 )
BC = 18.34°
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slope=m
(-3,4) x'=-3 y'=4
(4,-1) x"=4 y"=-1
slope formula :
m. (x'-x")=y'-y"
m. (-3-4)=4-(-1)
m.-7=4+1
m=-5/7
