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Luba_88 [7]
2 years ago
6

1. Which equation is true when m = 12?

Mathematics
1 answer:
kobusy [5.1K]2 years ago
7 0

Answer:

are there any more details? cant solve anything from what you have provided

Step-by-step explanation:

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SUPREME COURT The first Chief Justice of the U.S. Supreme Court, John Jay, served 2079 days
sashaice [31]

Answer:

John Roberts must serve a minimum of 12, 543 days to surpass John Mrshall's record of justice.

Step-by-step explanation:

John Marshall = 2079 + 10, 463 = 12, 542 days

Now, we have to add 1 more day to pass John Marshall because if we do not, we would only be on the same level as John Marshall and NOT EXCEEDING him.

4 0
3 years ago
What is the product? (3x-6) (2x^2 -7x+1)
STALIN [3.7K]

<u>Answer-</u>

\left(3x-6\right)\left(2x^2-7x+1\right)=6x^3-33x^2+45x-6

<u>Solution-</u>

Given the two polynomials are 3x-6, 2x^2 -7x+1

So their product will be,

=\left(3x-6\right)\left(2x^2-7x+1\right)

Distributing the Parentheses,

=3x\cdot \:2x^2+3x\left(-7x\right)+3x\cdot \:1+\left(-6\right)\cdot \:2x^2+\left(-6\right)\left(-7x\right)+\left(-6\right)\cdot \:1

Applying minus-plus rules,

=3\cdot \:2x^2x-3\cdot \:7xx+3\cdot \:1\cdot \:x-6\cdot \:2x^2+6\cdot \:7x-6\cdot \:1

Simplifying further,

=6x^3-33x^2+45x-6

4 0
3 years ago
Read 2 more answers
Consider the equation 5x^2-10x+c=0. What values of c result in the equation having a complex solutions? Represent your answer on
stiv31 [10]

Answer:

When we have a quadratic equation:

a*x^2 + b*x + c = 0

There is something called the determinant, and this is:

D = b^2 - 4*a*c

If D < 0, then the we will have complex solutions.

In our case, we have

5*x^2 - 10*x + c = 0

Then the determinant is:

D = (-10)^2 - 4*5*c = 100 - 4*5*c

And we want this to be smaller than zero, then let's find the value of c such that the determinant is exactly zero:

D = 0 = 100 - 4*5*c

    4*5*c = 100  

       20*c = 100

            c = 100/20 = 5

As c is multiplicating the negative term in the equation, if c increases, then we will have that D < 0.

This means that c must be larger than 5 if we want to have complex solutions,

c > 5.

I can not represent this in your number line, but this would be represented with a white dot in the five, that extends infinitely to the right, something like the image below:

8 0
2 years ago
What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The
max2010maxim [7]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

  • (6x+10°)
  • (x+17°)
  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

8 0
3 years ago
Polygon ABCD is plotted on a coordinate plane and then rotated 90° clockwise about point C to form polygon A′B′C′D′. Match each
horrorfan [7]

The vertices of ABCD after 90 degrees clockwise rotation about point C are: A' (0,6), B' (3,7), C' (4,6) and D' (4,3)

<h3>How to match the vertices of the polygon?</h3>

The image of the polygon ABCD is not given; however, the question can still be answered because the coordinates are known.

The vertices of polygon ABCD are given as:

A = (4, 6)

B = (5, 3)

C = (4, 2)

D = (1, 2)

The rule of rotation about point C is:

(x,y) = (a + b - y, x + b - a)

Where:

(a, b) = (4, 2) --- the point of rotation.

So, we have:

(x,y) = (4 + 2 - y, x + 4 - 2)

(x,y) = (6 - y, x + 2)

The above means that:

A' = (6 - 6, 4 + 2) = (0,6)

B' = (6 - 3, 5 + 2) = (3,7)

C' = (6 - 2, 4 + 2) = (4,6)

D' = (6 - 2, 1 + 2) = (4,3)

Hence, the image of the rotation and their vertices (i.e. coordinates) are:

A' = (0,6)

B' =  (3,7)

C' = (4,6)

D' =  (4,3)

Read more about rotation at:

brainly.com/question/4289712

#SPJ1

8 0
1 year ago
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