i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
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Answer:
-4
Step-by-step explanation:
-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10
^ ^
the ^ on the left is -5 and one number over is 4 which is the ^ on the right
the answer is 80
because 14500/18% is 80
C11 = (1×1) + (-1×3) = 1-3 = -2
C12 = (1×2) + (-1×4) = 2-4 = -2
C21 = (2×1) + (1×3) = 2+3 = 5
C22 = (2×2) + (1×4) = 4+4 = 8