Answer:
Step-by-step explanation:
The heights of neither the rectangular prism nor the triangular prism are given, so we don't know the volume of either.
If h is the height of the rectangular prism, then its volume is
6×8×h = 48
if the height of the triangular prism is h/2, then its volume is
(1/2)×24×8×(h/2) = 48
So we know the volumes are the same -- but we don't know what that volume is.
The area of the shaded sector is one-fourth of the area of the whole circle so:
area of shaded region
The area of the shaded region is 9pi units^2
Answer:
Step-by-step explanation:
Let us find the acceleration of box .
v² = u² + 2as
Putting the values
7² = 3² + 2 a x 14
a = 1.43 m /s²
If coefficient of friction be μ
force of friction = μ mg
= μ x 10 x 9.8
= 98μ
Net force pushing the box
= 85 - 98μ
Applying newton's second law
85 - 98μ = 10 x 1.43
98μ = 85 - 14.3
μ = .72
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