Answer:
1. 2(x+3)
2.x-3
3.2(x-3)
4.2-3x
5.x2+3
6.3-2
7.3+2
8.3x-2
9.3/x
10.x/3
Step-by-step explanation:
Answer:
<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>
Step-by-step explanation:
Distance run by the ostrich = 6 miles
Time the ostrich takes to run this distance = 12 minutes
Speed of the ostrich = Distance / Time
Speed of the ostrich = 6 miles / 12 minutes = 0.5 miles per minute
How far the ostrich could run in 40 minutes?
If the ostrich run 0.5 miles per minute, this is the formula:
Speed of the ostrich * 40 minutes = Distance
0.5 miles/minute * 40 minutes = 20 miles (Minutes is simplified in the numerator and the denominator on the left side)
<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
Answer:
John is running faster.
Step-by-step explanation:
Given that:
Average Speed of Anne = 6 miles per hour
Speed of John can be represented in the table below:
To find:
Who is running faster of the both i.e. Anne and John?
Solution:
Here, to find the faster runner we can compare the average speed of both the runners.
We are given that, average speed of Anne = 6 miles per hour
We will have to calculate the average speed of John to find the faster runner.
<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.
Total distance traveled by John = 11.5 - 1 = 10.5 miles
Total time taken by John = 1.5 hours
Average speed of John = 
Clearly Average speed of John is greater than that of Anne's.
Therefore, <em>John runs faster</em>.
