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kvasek [131]
3 years ago
7

Select all of the expressions that would be considered a polynomial ​

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Option B: y^{3}+y^{2}+7 y-10

Option D: \frac{3}{4} x^{2}+5 y^{5}

Solution:

<em><u>Polynomial definition:</u></em>

A polynomial can have constants, variables and exponents and fractional coefficient.

A polynomial cannot have fractional exponent, negative exponent and never division by a variable.

To select the expressions that would be considered as a polynomial.

Option A: 6 x+y+\sqrt{x}+3

√x is not, because the exponent is ½. Fractional exponents are not polynomials.

This is not a polynomial.

Option B: y^{3}+y^{2}+7 y-10

A polynomial can have constants, variables and exponents.

This is a polynomial.

Option C: 6 a^{\frac{1}{2}}+19

Fractional exponents are not polynomials.

This is not a polynomial.

Option D: \frac{3}{4} x^{2}+5 y^{5}

Fractional coefficients are allowed.

This is a polynomial.

Hence y^{3}+y^{2}+7 y-10 and \frac{3}{4} x^{2}+5 y^{5} are polynomial.

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*plz help it’s due tomorrow:)
ra1l [238]

Answer:

  • <em>The actual temperature after the freezer was on for five minutes could be </em><u><em>18ºF or 12ºF</em></u>

Explanation:

First, you must find the y-value returned by the line in the graph for a time (x) of five minutes, and then use the deviation of 3º to conclude the range of the real temperature.

<u>1. y- value at x = 5 min.</u>

The trend line (blue line in the graph) passes through the point (5,15), which means that it predicts a temperature of 15ºF when the time (x) is 5 minutes, or five minutes after the freezer was turned on.

<u>2. Actual temperature value</u>

It is stated that the temperature was actually three degrees from what the trend line shows, that means that the actual temperature could be 3ºF more or 3ºF less than the predicted temperature of 15ºF.

Mathematically:

  • Temperature = 15ºF ± 3ºF

  • Temparature = 15ºF + 3ºF or 15ºF - 3ºF

  • Temperature = 18ºF or 12ºF ← answer.
8 0
4 years ago
There are 130 people in a
Sonja [21]

Answer:

If 11 people use all three facilities, this means:

22 − 11 or 11 are using the gym and the pool but no the track,

29 − 11 or 18 are using the pool and the track but no the gym,

25 − 11 or 14 are using the gym and the track but no the pool.

How many people use the gym only?

130 − (14 + 11 + 11) = 94

How many people use the pool only?

62 − (18 + 11 + 11) = 22

How many people use the track only?

58 − (14 + 11 + 18) = 15

How many people go in for sports?

94 + 22 + 15 + 11 + 14 + 18 + 11 = 185

How many people use exactly one of the facilities?

94 + 22 + 15 = 131

What is the probability that the person uses exactly one of the facilities?

= 131/185 ≈ 0.7081

Step-by-step explanation:

its a bit confusing

Hope It Helps !!!!

7 0
2 years ago
Please help !!<br><br> find the volume
RoseWind [281]
It’s 102in sorry if I’m late to answer
6 0
3 years ago
4a2b-6ab2 +12ab3 <br><br><br>Factorise​
zlopas [31]
38ab you gotta calculate the product which is 8 and 36 then collect like terms and you get 38ab
3 0
3 years ago
PLS HELP I IWLL GIVE BRAINLIEST
salantis [7]

I hope it helps liked it and make it brainliest

so the answer is:y=sin (∅)

3 0
2 years ago
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