-1/2
(2,-5) (4,-6) =-6+5/4-2=
-1/2
Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))
(X,Y) = (-2,8) this the answer
Step-by-step explanation:
EF = 6x - 4
and it is also the combination of EG and GF.
so,
6x - 4 = EG + GF = EG + 13
6x = EG + 17
now, we have additional information. EF bisects CD. that means it cuts CD in half.
and that means both banks must be off equal size.
5x - 1 = 7x -13
12 = 2x
x = 6
so, back to the first problem
6×6 = EG + 17
36 = EG + 17
19 = EG
Find the absolute value vertex. In this case, the vertex for y=|x−5|y=|x-5| is (5,0)(5,0).
(5,0)(5,0)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
(−∞,∞)(-∞,∞)
{x|x∈R}{x|x∈ℝ}
For each xx value, there is one yy value. Select few xx values from the domain. It would be more useful to select the values so that they are around the xx value of the absolute valuevertex.
xy3241506172
