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love history [14]
3 years ago
14

Specify the domain for the function !!! 10 points - Help needed !

Mathematics
1 answer:
leva [86]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The domain for the function is all the real numbers,

Domain:(-∞,∞)

<h2>Why?</h2>

Since we are working with fractions, the only restriction that we will have for the function is when the denominator of the function tends to 0.

We are given the function:

f(x)=\frac{1}{x^{2}-5x+25 }

Where, the denominator is given by the expression:

x^{2}-5x+25

For the given expression (quadratic equation), we have that:

a=1\\b=-5\\c=25

Calculating the discriminat of the quadratic function, in order to know if the denominator of the function has roots (zeroes) at the real numbers, we have:

Discriminant=b^{2} -4ac

Discriminant=-5^{2} -4(1)(25)

Discriminant=25 -100=-75

Now, as we know, if the discriminant of a quadratic function is less than 0, the quadratic function has no roots in the real numbers.

Therefore, since the denominator (quadratic function) has no roots in the real numbers, the domain for the function will be equal to all the real numbers.

Domain:(-∞,∞)

Hence, the answer is the third option, the domain for the function is all the real numbers,

Domain:(-∞,∞)

Have a nice day!

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a tourist drove his car for the total of 17.5 hours while on a 3-day vacation on the first day he drove 4.5 hours in the second
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Answer:

1.75 hours

Step-by-step explanation:

Time for day 1 : 4.5 hrs

Time for day 2: (4.5 ×2.5)

Time for day 3: let it be denoted by a variable ,say T.

Total Time= 17.5

(Time for day 1 ) + (Time for day 2) +(Time for day 3) =17.5

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T=17.5-15.75

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[20 pts] evaluate the logarithm log(6)1/36​, show work pls!
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Answer:

\large\boxed{\log_6\dfrac{1}{36}=-2}

Step-by-step explanation:

\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2

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Kishore bought a basket containing 30 orangs for rs 310. If he sells the orangs at rs 12 each , what Would be it's profit or los
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Given : Kishore bought a basket containing 30 oranges for rs 310. If he sells the oranges at rs 12 each , what Would be it's profit or loss?

Solution :

Cost price of oranges = rs.310

As we know that each oranges cost rs.12

So, selling price of oranges is 30 × 12 = rs.360

Now, <u>finding profit or loss</u>

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