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Crazy boy [7]
4 years ago
15

A dozen eggs cost $1.19. about how much does one egg cost?

Mathematics
1 answer:
Alex777 [14]4 years ago
3 0
They'll be .09 cents
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Levi works as a salesperson at an electronics store and sells phones and phone accessories. Levi earns a $8 commission for every
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8p + 3a = 213 and p + a = 41 are the two required equations which will give us the number of phones and accessories sold by Levi.

<u>Solution:</u>

Levi earns a $8 commission for every phone he sells and a $3 commission for every accessory he sells.

On a given day, Levi made a total of $213 in commission from selling a total of 41 phones and accessories.  

We have been asked to write a system of equations that could be used to determine the number of phones sold and the number of accessories sold. We also have to define the variables that you use to write the system.

Let us denote the number of phones as ‘p’ and number of accessories as ‘a’

So, we can write the following equations from the given data:

Given that levi made $ 213 commission

8p + 3a = 213

And,  Levi sold 41 phones and accessories. So we can frame a equation as follows:

p + a = 41

These two equations can be used and solved to determine the number of phones and accessories sold.

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Rotation 90° clockwise about the origin
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Step-by-step explanation:

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This is algebra 2 it’s growth &amp; decay. I need help
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<h3>Part 1:</h3>

So firstly, remember that the <em>a variable is the initial value.</em> Since we start off with 6.08 billion, <u>6.08 billion is the a variable.</u>

Next, since this is a <em>growth by 1.26%</em>, add 1 and 0.0126 (1.26% in decimal form) together to get 1.0126. <u>1.0126 is the b variable.</u>

Putting it together, <u>the function is A(t)=6.08(1.0126)^t</u>

<h3>Part 2:</h3>

Since 2020 is 20 years from 2000, plug in 20 into the t variable of the prior function to solve:

A(20)=6.08(1.0126)^{20}\\ A(20)=7.81

In context, <u>in 2020 the population will be 7.81 billion.</u>

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4 years ago
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