Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.
Explanation:
Given: A quadratic equation, kx2 - 14x + 8 = 0
Let the two zeros of the equation be α and β.
According to the given question, if one of the roots is α the other root will be 6α.
Thus, β = 6α
Hence, the two zeros are α and 6α.
We know that for a given quadratic equation ax2 + bx + c = 0
The sum of the zeros is expressed as,
α + β = - b / a
The product of the zeros is expressed as,
αβ = c / a
For the given quadratic equation kx2 - 14x + 8 = 0,
a = k, b = -14, c = 8
The sum of the zeros is:
α + 6α = 14 / k [Since the two zeros are α and 6α]
⇒ 7α = 14 / k
⇒ α = 2 / k --------------- (1)
The product of the zeros is:
⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]
⇒ 6α 2 = 8 / k
⇒ 6 (2 / k)2 = 8 / k [From (1)]
⇒ 6 × (4 / k) = 8
⇒ k = 24 / 8
⇒ k = 3
Answer:
5 times 3 =15lb
Step-by-step explanation:
Answer:
50 grams
Step-by-step explanation:
Let the amount of cheese required by the recipe be "x"
Ann increased 60% from original amount and then used up 80 grams. Thus:
<em>Original, increased by 60%, became 80</em>
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This translated to algebraic equation would be:
x + 0.6x = 80
<u>Note:</u> 60% = 60/100 = 0.6
So we can solve the above equation for "x" and get our answer. Shown below:

Hence,
the recipe required 50 grams of cheese
Answer:
There are 1500 non fiction books and 500 fiction books currently in the store.
Step-by-step explanation:
Given:
Total Number of books = 2000
Let the number of fiction books be 'x'.
Now given:
There are 3 times as many non-fiction books as fiction books.
Number of non fiction books = 
We need to find the number of non-fiction and fiction books.
Solution:
Now we know that;
Total Number of books is equal to sum of the number of non-fiction and fiction books.
framing in equation form we get;

Dividing both side by 4 we get;

Number of fiction books = 500
Number of non fiction books = 
Hence There are 1500 non fiction books and 500 fiction books currently in the store.
Answer:
2x² - 3x - 2
Explain:
Use the FOIL method: (a +b)(c +d) = ac + ad +bc +bd.
2x² + x - 4x - 2
Collect like terms.
2x² + (x - 4x) - 2
Simplify.
2x² - 3x - 2