Answer:
y = 4x+6
The input is 11 when the output is 50
Step-by-step explanation:
We need to find the slope of this function using 2 points
(3,18) and (0,6) are two points
m = (y2-y1)/(x2-x1) is the formula for slope
=(6-18)/(0-3)
-12/-3
=4
The slope is 4
We know the y intercept. It is the value when x =0. The y intercept is 6
We can use the slope intercept form of the equation
y = mx+b, where m is the slope and b is the y intercept.
y = 4x+6
We want to know the input when the output is 50 (or y=50)
50 = 4x+6
Subtract 6 from each side
50-6 = 4x+6-6
44 = 4x
Divide by 4
44/4 = 4x/4
11=x
The input is 11
Answer:
69 <-- quotient
---
Step-by-step explanation:
8)555
48
--
75
72
--
3 <-- remainder
For the answer to the question above, <span>
5x3 (the hundreds digit)= 15
so 3+x+y=15. 15-3=12. x+y=12.
No even number + odd number can be = 12, so both digits must be odd.
That leaves us with 3+3+z=15, 3+3+x =15 and 3+5+y= 15. 3+1+9 (highest odd digit)= 13 so that is wrong.
3+3+9= 15, but there is a double digit, so wrong again. 3+5+7=15. 357 is the answer.</span>
Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly