Bring them to the same denominator and solve for x
The answer to question 5 is -3.
The answer to question 9 is -5.<span>
</span>The answer to question 7 is 28x^3y^4.
Answer:

Step-by-step explanation:

Answer:
A
Step-by-step explanation:
The easiest way to figure this out is to substitute in the variables. So for a, 2=-5+7 is correct, and 7=0+7 is correct as well. If you were to look at the other answers, you would see that the equation would not match up. Hope this helps!
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