Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
24/36
There are 36 students from 14-17 in total. 24 skip breakfast so. 24/36
2 out of 50 are defective.
Divide 2 by 50: 2/50 = 0.04
Now multiply the total quantity by that:
2000 x 0.04 = 80
80 are likely to be defective.
Answer:
A = (x + 7)(x + 9)
Step-by-step explanation:
Let the width w = x
then length l = w + 4 = x + 4
Area = length x width
= x(x+4)
Then the the width is increased by 7 units and the length increased by 5 units.
w = x + 7
l = (x + 4) + 5 =x + 9
A = (x + 7)(x + 9)
Answer:
1 or 0
Step-by-step explanation:
8 x b = 13
You can't divide 8 by two because that equals 16 so 8 x 1 is less than 8.
And 8 x 0 is 0
