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juin [17]
4 years ago
5

Find the trace on the xy-plane of the sphere having center at (−1, 3, −1) and radius 2.

Mathematics
1 answer:
ra1l [238]4 years ago
3 0
Hi,

The sphere has for equation :(x+1)²+(y-3)²+(z+1)²=4
The xy plane has for equation z=0
The trace off the sphere in the xyplane is
(x+1)²+(y-3)²=4 (the circle of center (-1,3,0) &nd 2 as radius)


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10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
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The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

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3 years ago
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