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3 years ago

Balance the following redox reaction by ion electron method.I2+ HNO3 = HI03+ NO2+ H20

Mathematics

1 answer:

Ad libitum [116K]3 years ago

7 0

Answer:

BRO I DONT KNOW SORY I NEED POINTS

Step-by-step explanation:

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In a circle of any size, what ratio does

Len [333]

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2 years ago

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Find the area between y=(x-2)ex and the x-axis from x=2 to x=4.

mojhsa [17]

Answer:

$e^4+e^2$

Step-by-step explanation:

It can be found by integral.

First let's find the intersection points.

$(x-2)e^x = 0$

Only intersection point is x = 2.

And it is asked to find the area in the interval (2, 4).

$\int\limits^4_2 (x-2)e^x \,dx=?$

We will use integration by parts.

$x-2=u\\dx=du\\e^xdx=dv\\e^x=v$

$\int\limits^4_2 (x-2)e^x \,dx=uv-\int vdu=(x-2)e^x-\int e^xdx=(x-2)e^x-e^x=\\\\=(x-3)e^x|^4_2=(4-3)e^4-(2-3)e^2=e^4+e^2$

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3 years ago

Which line has a slope of 0? A: x = 1 B: 3y + 6x = 0 C: y = x D: y = -5

padilas [110]

Answer:

D) y=-5

Step-by-step explanation:

..............

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3 years ago

What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?

Dafna1 [17]

Step 1

<u>Find the slope of the given line</u>

we have

$3x+4y=15$

Isolate the variable y

Subtract $3x$ both sides

$3x+4y-3x=15-3x$

$4y=-3x+15$

Divide by $4$ both sides

$y=-\frac{3}{4}x+ \frac{15}{4}$

the slope of the given line is

$m=-\frac{3}{4}$

Step 2

Find the equation of the line that passes through the point $(8,-2)$ and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{3}{4}$

$(x1,y1)=(8,-2)$

substitute in the equation

$y+2=-\frac{3}{4}(x-8)$

$y=-\frac{3}{4}x+6-2$

$y=-\frac{3}{4}x+4$ or $3x+4y=16$

therefore

<u>the answer is</u>

$y=-\frac{3}{4}x+4$

$3x+4y=16$

8 0

3 years ago

Balance the following redox reaction by ion electron method.I2+ HNO3 = HI03+ NO2+ H20​

Balance the following redox reaction by ion electron method.I2+ HNO3 = HI03+ NO2+ H20