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Levart [38]
3 years ago
12

Which two kinds of whales have the closest number alive?

Mathematics
1 answer:
tangare [24]3 years ago
5 0

The answer is: Fin whale and Sei whale.

The explanation for this exercise is shown below:

To solve this problem you must use the table given in the figure attached, which shows the numbers of whales alive today. In the column titled "Population" you can see these numbers.

Therefore, when you analize the table, you can conclude that the two kinds of whales that have the closest number alive are: Fin whale, with a population of 55,000 and Sei whale, with a population of 54,000.

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Which of the following fractions is equivalent to 0.45?<br> 45/1000<br> 3/10<br> 9/20<br> 5/9
-Dominant- [34]
In Order To Find The Answer To this quetsion,you have to divide each set of fractions by them selfs and there for 9/20 and 45/1000 are the closest ones.
Divide 45/1000=0.045 but Divide 9/20=0.45 and that is your answer.
8 0
3 years ago
Read 2 more answers
A pool was filled with 8.2 times 10 Superscript 3 gallons from one hose and 9.4 times 10 Superscript 3 gallons from another hose
prisoha [69]

Answer:

1.76 x 10⁴ gallons

Step-by-step explanation:

8.2 x 10³ + 9.4 x 10³ = 17.6 x 10³

Although correct 17.6 x 10³ is not in scientific notation

which is

1.76 x 10⁴ gallons

5 0
3 years ago
How do you simplify an Algebraic expression ?
NeTakaya

Answer:

You can solve one by... it's hard to explain So i'll just show you

Step-by-step explanation:

Here's an example,

2x+7=4+5x

First you subtract the variables on both sides (lower variable)

2x+7=4+5x

-2x       -2x

Which will leave you

7=4+3x

The subtract the whole number on each side (lower number)

7=4+3x

-4   -4

Which will leave you

3=+3x

Then you divide on both sides

3/3   3/3

which should leave you

x=1

5 0
3 years ago
A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimat
Leona [35]

Answer:

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

Step-by-step explanation:

First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)

n = \sigma \cdot A

Where:

\sigma - Surface density, measured in trees per square meter.

A - Total area, measured in square meters.

Given that \sigma = \frac{1}{20}\,\frac{tree}{m^{2}} and A = 24\,h, the total amount of fir trees is:

n = \left(\frac{1}{20}\,\frac{trees}{m^{2}}  \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)

n = 12000\,trees

It is known that one-tenth of the tress are cut, whose amount is:

n_{c} = 0.1 \cdot n

n_{c} = 0.1 \cdot (12000\,trees)

n_{c} = 1200\,trees

If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:

y = S\cdot n_{c}

Where:

S - Yield of the tress, measured in board-feet per tree.

n_{c} - Amount of trees that will be cut, measured in trees.

If n_{c} = 1200\,trees and S = 300\,\frac{b-ft}{tree}, then:

y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)

y = 360000\,b-ft

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

8 0
3 years ago
How do you estimate a length
WARRIOR [948]
A little tip is this 
if its like 1.4 inches it goes to 1 inch but if it goes to 1.5 inches it goes to two

8 0
3 years ago
Read 2 more answers
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