Answer: 50.24 cm^2
Step-by-step explanation:
This can be translated to:
An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of the coin?
The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.
The perimeter of the box is 24 cm, and the perimeter of a square is equal to:
P = 4*L
where L is the side lenght of the square.
24 cm = 4*L
L = 24cm/4 = 8cm
Now we know that the diameter of the coin is 8cm
Now, the area of a circle (the coin) is equal to:
A = 3.14*(d/2)^2
where d is the diameter, so we have:
A = 3.14*(4cm)^2 = 50.24 cm^2
Volume of Pyramid = (1/3)*(base area) * height.
32 ft³ = (1/3)*(4*4)* h. Since Pyramid is square based.
32 = (16/3)*h
16h/3 = 32
h = 32*3/16
h = 6
Height = 6 feet. Option C.
Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure 
= 14.7
Pressure at 4000 ft = 12.6
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) = 
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 =
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 × ----- (2)
Product of k & h is
k h = 3.85 × × 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10
This is the value of pressure at an altitude of 10000 ft.
Selection C is the appropriate choice.
