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3 years ago

The value of a $25,000 car depreciates at a rate of 12% per year. What will the car be worth in 5 years?

Mathematics

2 answers:

navik [9.2K]3 years ago

8 0

Answer: 13,193.30$

Step-by-step explanation YOU TAKE 12 % OFF THE ANSWER THEN DO IT AGAIN SO IT LEAVE YOU WITH

Scorpion4ik [409]3 years ago

3 0

The formula for depreciation is:

Value = Starting value x (1 - rate)^time

Using the given values:

Value = 25,000 x (1-0.12)^5

Value = 25,000 x 0.88^5

Value = $13,193.30 (Round the answer as needed)

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The value of a car is $30,000 and depreciates at a rate of 6.5% each year.

navik [9.2K]

Answer:$20250

Step-by-step explanation:

6.5% of 30000

6.5/100 x 30000

(6.5 x 30000)/100

195000/100=1950

First year depreciation 30000-1950=28050

Second year=28050-1950=26100

Third year=26100-1950=24150

Fourth year=24150-1950=22200

Fifth year=22200-1950=20250

7 0

3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

2) Evaluate the given numerical expression. A) 9 B) 12 C) 14 D) 21

eduard

Answer:

$\boxed{\sf{14}}$

Step-by-step explanation:

$\boxed{\underline{\text{ORDER OF OPERATIONS:}}}$

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

PEMDAS

Parentheses
Exponents
Multiply
Divide
Add
Subtract

BODMAS

Brackets
Order
Divide
Add
Subtract

First, do parentheses.

3+6*(5+4)÷3-7

(5+4)=9

$\Longrightarrow: \sf{3+6* 9\div 3-7}$

Do multiply and divide.

6*9=54

54/3=18

Then, rewrite the problem down.

$\Longrightarrow: \sf{3+18-7}$

Add.

$\sf{3+18=21}$

$\sf{21-7=\boxed{\sf{14}}$

$\Longrightarrow: \boxed{\sf{14}}$

Therefore, the correct answer is "C. 14".

I hope this helps, let me know if you have any questions.

8 0

2 years ago

If two ratio are equal they form a ___. I need help IMMEDIATELY. I am going to my grandmas and I need to finish quickly.

Alex17521 [72]

two ratios are equal and form a proportion.

8 0

3 years ago

Read 2 more answers

gYou have a six-sided die that you roll once and ob- serve the number of dots facing upwards. What is the sample space

Aleonysh [2.5K]

Hey!

The sample space would be sides 1, 2, 3, 4, 5, and 6, or 1-6.

A sample space is a range of possible values.

Hope this helps! :D

5 0

3 years ago