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My name is Ann [436]
3 years ago
11

Experts say you should carry a life insurance policy that is 8-10 times your gross annual salary. If your gross monthly salary i

s $2458.00, what is the least amount of life insurance you should carry? (Circle the answer choice)
a. $200,000
b. $150,000
c. $300,000
d. $250,000
e. $100,000
f. $350,000
Mathematics
2 answers:
Alchen [17]3 years ago
6 0
<span>d. $250,000....................................</span>
Andrej [43]3 years ago
5 0
D. $2,458*12=29,496*8=$235,968 and then the closest number above that bc its between 8-10 times not 7-8 or 6-8 or something like that.
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Step-by-step explanation:

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A person drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 200 times. Here are the observed f
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Answer:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

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Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the frequencies

H1: There is a difference in the frequencies

The level of significance assumed for this case is \alpha=0.01

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The observed values are:

Value            1     2    3    4    5     6

Frequency  26  32  44  37  27  34

And the expected values are for this case the same E_i = \frac{200}{6}= 33.33

And now we can calculate the statistic:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

p_v = P(\chi^2_{5} >6.7)=0.244

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

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4 years ago
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How does one determine a TVs height and width when we only know the diagonal measurement
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Answer:


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