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3 years ago

How do you write 31/50 as a percentage7k

2 answers:

4 0

31/50

31 ÷ 50 = 0.62

0.62 x 100 = 62%

So the answer is 62%

Hope this helps I didn't know if the 7k was apart of the problem or a typo

IceJOKER [234]3 years ago

4 0

31/50 as a percentage is 62%.

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ms shah grades 3402 math problems during 5th period this is 54% of the total number of problems she need to grade what is the to

olga_2 [115]

The total number of problems she needs to grade is 6.

6 0

2 years ago

At a certain zoo, the average mass of one blue whale is measured to be 1.9 × 105

professor190 [17]

Answer:

2.7930 × $10^{4}$

Step-by-step explanation:

1.9 × 105 × 140 = 27,930

Scientific notation: 2.7930 × $10^{4}$

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2 years ago

What is the value of the expression?

const2013 [10]

Answer:

Step-by-step explanation:

Use the correct order of operations and do one step at a time to avoid making mistakes.

$16 \div 4 + 2^3 \times 5 - 3 =$

$= 4 + 8 \times 5 - 3$

$= 4 + 40 - 3$

$= 44 - 3$

$= 41$

6 0

3 years ago

Read 2 more answers

Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC

Marysya12 [62]

BC is 10 units and AC is $5+5\sqrt{3}$ units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}$
AB is opposite to ∠C
BC is opposite to ∠A
AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ $\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

∵ AB = $5\sqrt{2}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}$

- By using cross multiplication

∴ (BC) × sin(30) = $5\sqrt{2}$ × sin(45)

∵ sin(30) = 0.5 and sin(45) = $\frac{1}{\sqrt{2}}$

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ $\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}$

- By using cross multiplication

∴ (AC) × sin(30) = $5\sqrt{2}$ × sin(105)

∵ sin(105) = $\frac{\sqrt{6}+\sqrt{2}}{4}$

∴ 0.5 (AC) = $\frac{5+5\sqrt{3}}{2}$

- Divide both sides by 0.5

∴ AC = $5+5\sqrt{3}$ units

BC is 10 units and AC is $5+5\sqrt{3}$ units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0

3 years ago

What i -5 5/12 written a a decimal

Helen [10]

-5 5/12 =-5.416
(: :)
(:

7 0

3 years ago